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2x+5=-x^2+3x-3
We move all terms to the left:
2x+5-(-x^2+3x-3)=0
We get rid of parentheses
x^2-3x+2x+3+5=0
We add all the numbers together, and all the variables
x^2-1x+8=0
a = 1; b = -1; c = +8;
Δ = b2-4ac
Δ = -12-4·1·8
Δ = -31
Delta is less than zero, so there is no solution for the equation
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